this post was submitted on 27 Jul 2024
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is that how the alu performs multiplication? with a binary adder?
Yes. Typically, to multiply two n-bit numbers, you need n - 1 n-bit adders. You basically do long multiplication.
I'd upload an image but either voyager or my instance won't let me for some reason, so sorry if this doesn't embed right
Embedded just fine on my end (Jerboa)
this makes sense
Shouldn't you be able to get away with two 2n bit adders and recursion?
Conceptually yes, but you can achieve better efficiency by putting multiple adders together with e.g. a Wallace tree.
There are more efficient ways to expand adders than simply chaining them as well.
Gosh, time to rebuild my ALU again..